F(x)=2x-5-4x^2

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Solution for F(x)=2x-5-4x^2 equation: 



(F)=2F-5-4F^2

We move all terms to the left:

(F)-(2F-5-4F^2)=0

We get rid of parentheses

4F^2-2F+F+5=0

We add all the numbers together, and all the variables

4F^2-1F+5=0

a = 4; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·4·5
Δ = -79
Delta is less than zero, so there is no solution for the equation

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